# Line slope calculator 4x+3y=50

**Straight line given by points A[5; 10] and B[8; 6]**

## Calculation:

**Slope-intercept form of line:**y = -1.3333x+16.6667

**Canonical form of the line equation:**4x+3y-50 = 0

**Parametric form of the line equation:**

x = 3t+5

y = -4t+10 ; t ∈ R

**Slope:**m = -1.3333

**Slope angle of line: φ =**-53°7'48″ = -0.9273 rad

**X intercept:**x

_{0}= 12.5

**Y intercept:**y

_{0}= q = 16.6667

**Distance line from the origin:**d

_{0}= 10

**The length of the segment AB: |AB| =**5

**Vector: AB =**(3; -4)

**Normal vector: n =**(4; 3)

**Midpoint of the segment AB: M =**[6.5; 8]

**Perpendicular Bisector equation:**3x-4y+12.5 = 0

**Vector OA = (5; 10) ; |OA| = 11.1803**

**Vector OB = (8; 6) ; |OB| = 10**

**Scalar product OA .OB = 100**

**Angle ∠ AOB = 26°33'54″ = 0.4636 rad**